There is mathematical calculation involved in it. Simply follow the below given 5 steps to find the day for any given date from years 1752 to 2099.
Take the last two digits of the year and add 1/4 of it to the same. Ignore the remainder.
Let's take 14 Nov, 1977 as an example. Take last two digits of year i.e. 77. 1/4 of it is 19.25. Ignore 0.25 and add 19 to 77. The answer is 96 (77 + 19).
Let's take 14 Nov, 1977 as an example. Take last two digits of year i.e. 77. 1/4 of it is 19.25. Ignore 0.25 and add 19 to 77. The answer is 96 (77 + 19).
Add the given day of the month to it.
The answer is 110 (96 + 14).
The answer is 110 (96 + 14).
Now, add the month value to it. Month values are as given below:
· January - if Leap Year then 0 else 1
· February - if Leap Year then 3 else 4
· March - 4
· April - 0
· May - 2
· June - 5
· July - 0
· August - 3
· September - 6
· October - 1
· November - 4
· December - 6
The answer is 114 (110 + 4)
Add the Century value as given below:
· 18th Century - 4
· 19th Century - 2
· 20th Century - 0
· 21th Century - 6
The answer is 114 (114 + 0)
Divide the answer by 7. Ignore the quotient and take the remainder. Based on the value of remainder, you can tell the day.
· 1 - Sunday
· 2 - Monday
· 3 - Tuesday
· 4 - Wednesday
· 5 - Thursday
· 6 - Friday
· 0 - Saturday
Remainder after dividing 114 by 7 is 2. Hence, it was Monday on 14 Nov, 1977
Karan
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